-17/5,k^2=9/5

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Solution for -17/5,k^2=9/5 equation: 



-17/5.k^2=9/5

We move all terms to the left:

-17/5.k^2-(9/5)=0



Domain of the equation: 5.k^2!=0

k^2!=0/5.

k^2!=√0

k!=0

k∈R



We add all the numbers together, and all the variables

-17/5.k^2-(+9/5)=0

We get rid of parentheses

-17/5.k^2-9/5=0

We calculate fractions


=0

k=0/1

k=0

Równanie nie ma rozwiązania

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